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Old 09-22-2004, 03:39 PM   #1 (permalink)
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Genetics

If you have the mRNA strand:

AUGUUUGGGCCCAAAUAACCGG

How many amino acids does it produce.

AUG would produce Met
UUU would make Phe
GGG would make Gly
AAA would make Pro
UAA would be the stop codone

The problem is that AUG is the standard start codon, does it just count as the start codon or does it produce an amino acid also. Thanks for the help
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Old 09-23-2004, 08:33 PM   #2 (permalink)
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UAG is the start codon for every translated polypeptide and it codes for the amino acid methionine.

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Old 09-26-2004, 01:59 PM   #3 (permalink)
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saltfish is correct. The AUG is translated into met.

Don't know what this if for, but if it is for a class and the teacher is trying to make it a trick question, you also need to look at the other reading frames (granted there is no start codon in the other reading frames, but you didn't stipulate that this sequence wasn't taken from the middle of a gene):

1st Open reading frame (ORF): AUG UUU GGG CCC AAA UAA CCG

2nd ORF: UGU UUG GGC CCA AAU AAC CCG

3rd ORF: GUU UGG GCC CAA AUA ACC

BTW, many proteins (especially viral proteins where they have to pack as much as possible into a small genome) are translated from overlapping reading frames. So that in some cases, one strand of RNA can produce three separate proteins.

Last edited by hokieian; 09-26-2004 at 02:02 PM..
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Old 10-24-2004, 10:14 PM   #4 (permalink)
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Quote:
Originally Posted by hokieian
saltfish is correct. The AUG is translated into met.

Don't know what this if for, but if it is for a class and the teacher is trying to make it a trick question, you also need to look at the other reading frames (granted there is no start codon in the other reading frames, but you didn't stipulate that this sequence wasn't taken from the middle of a gene):

1st Open reading frame (ORF): AUG UUU GGG CCC AAA UAA CCG

2nd ORF: UGU UUG GGC CCA AAU AAC CCG

3rd ORF: GUU UGG GCC CAA AUA ACC

BTW, many proteins (especially viral proteins where they have to pack as much as possible into a small genome) are translated from overlapping reading frames. So that in some cases, one strand of RNA can produce three separate proteins.



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Old 10-25-2004, 06:30 AM   #5 (permalink)
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Quote:
Originally Posted by heccubusiv
If you have the mRNA strand:

AUGUUUGGGCCCAAAUAACCGG

How many amino acids does it produce.

AUG would produce Met
UUU would make Phe
GGG would make Gly
AAA would make Pro
UAA would be the stop codone

The problem is that AUG is the standard start codon, does it just count as the start codon or does it produce an amino acid also. Thanks for the help
5 amino acids would be produced, Methionine-Phenylalanine-Glycine-Proline-Arginine. The stop codon would then end the chain, and no further codons would be translated (so you wouldn't stop this chain, and then pick up the next codon, which is a proline. You would just stop.)

Also, AAA is Lysine, not Proline. Proline is CCC, CCU, CCA, and CCG.

AUG as the start codon does indeed attach Methionine to the beginning of the amino acid chain. In several species, E. Coli is one I believe, it will be N-formylated for f(ormyl)-Methioinine (fMet) but that probably wouldn't be necessary to include unless the conditions of the problem were specific enough to tell you that it would be that way.
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