Electrical circuit help - Tilted Forum Project Discussion Community

Jakejake · 09-24-2003, 09:06 AM

Hi there, here is the problem:

Now part (a) is easy enough, I've done that - Because each side has two 10kOhm resistors then V1 and V2 are equal (5V each) and you can ignore the middle resistor when calculating the current.
Part (b) is where I am stuck. Thing is, I seem to remember doing questions like this a while ago, and I think that there might be something very simple that I am missing when trying to do this.
Anyone got any ideas on how to do (b)?

Thanks a lot in advance

Robbie

goddfather40 · 09-24-2003, 07:34 PM

part (b) is a typical resistive bridge circuit.

The basic way to do it is to convert the delta resistor configurations into Y resistor configurations using the conversions.

See the website below:
http://www.allaboutcircuits.com/vol_1/chpt_10/12.html

An easy way to do it is do use Thevenin and Norton equivalents.

Kadath · 09-24-2003, 08:38 PM

Why Lord, why did I look at this?! I knew it would kill my soul!!
Stupid EE degree, good for nothing, grumble grumble...

Jakejake · 09-25-2003, 01:44 AM

Quote:

Originally posted by goddfather40
part (b) is a typical resistive bridge circuit.

The basic way to do it is to convert the delta resistor configurations into Y resistor configurations using the conversions.

See the website below:
http://www.allaboutcircuits.com/vol_1/chpt_10/12.html

An easy way to do it is do use Thevenin and Norton equivalents.

Wow, thanks a lot

That is a great help

In fact, that whole site looks very useful. Thanks again.

Sapper · 09-25-2003, 05:10 AM

I would have thought that it were a resistors in parallel and serial type problem ... now we see why I don't do EE

cheerios · 09-25-2003, 09:02 AM

/me had to drop electric circuits, but aced digital... so come back when they're gates, not resistors! :P

iamjero · 09-25-2003, 09:40 AM

Meltdown meltdown!!! Hurry click back botton before its too late

Kadath · 09-25-2003, 11:12 AM

Quote:

Originally posted by cheerios
/me had to drop electric circuits, but aced digital... so come back when they're gates, not resistors! :P

Amen to that, sister. Analog hard, digital easy. Logic > Math any day.

Xell101 · 09-25-2003, 01:15 PM

Quote:

Logic > Math any day.

???...Math = Logic

CSflim · 09-25-2003, 01:28 PM

Quote:

Originally posted by Xell101
???...Math = Logic

dunno...presumably it means
Math describing physical systems vs. Boolean Algebra?

cheerios · 09-25-2003, 09:33 PM

theory > reality may be better? it's nice to be in a world where it's black and white, zero and one. no question. no ... well... MAYBE it's a one... it's one or the other, no middle. plus, it's the beginnings of computing theory. if I'm feeling evil, maybe I'll put up the Turing Problem for ya, one of these days

Kadath · 09-26-2003, 05:36 AM

To clear up:
As cheerios knows, digital circuits are a big boolean expression. Analog circuits are a whole bunch of complicated math (including imaginary numbers) in which you have to do all sorts of calculations. While I suppose a Boolean expression is math...whatever. I've gotten depressed thinking about this. But logic != math.

09-24-2003, 09:06 AM	#1 (permalink)
Jakejake Crazy	Electrical circuit help Hi there, here is the problem: Now part (a) is easy enough, I've done that - Because each side has two 10kOhm resistors then V1 and V2 are equal (5V each) and you can ignore the middle resistor when calculating the current. Part (b) is where I am stuck. Thing is, I seem to remember doing questions like this a while ago, and I think that there might be something very simple that I am missing when trying to do this. Anyone got any ideas on how to do (b)? Thanks a lot in advance Robbie

09-24-2003, 07:34 PM	#2 (permalink)
goddfather40 Llama Location: Cali-for-nye-a	part (b) is a typical resistive bridge circuit. The basic way to do it is to convert the delta resistor configurations into Y resistor configurations using the conversions. See the website below: http://www.allaboutcircuits.com/vol_1/chpt_10/12.html An easy way to do it is do use Thevenin and Norton equivalents. __________________ My name is goddfather40 and I approved this message. I got ho's and I got bitches, In C++ I branch with switches -MC Plus+

09-24-2003, 08:38 PM	#3 (permalink)
Kadath Muffled Location: Camazotz	Why Lord, why did I look at this?! I knew it would kill my soul!! Stupid EE degree, good for nothing, grumble grumble... __________________ it's quiet in here

09-25-2003, 05:10 AM	#5 (permalink)
Sapper Insane Location: The Internet	I would have thought that it were a resistors in parallel and serial type problem ... now we see why I don't do EE __________________ rm -f /bin/laden

09-25-2003, 09:40 AM	#7 (permalink)
iamjero Insane Location: New Orleans/Oakland/San Diego/Chicago	Meltdown meltdown!!! Hurry click back botton before its too late __________________ "Ideas are far more powerful than guns. We don't allow our enemies to have guns, why should we allow them to have ideas?" - Joseph Stalin

09-25-2003, 09:02 AM	#6 (permalink)
cheerios Banned Location: 'bout 2 feet from my iMac	/me had to drop electric circuits, but aced digital... so come back when they're gates, not resistors! :P

09-25-2003, 09:33 PM	#11 (permalink)
cheerios Banned Location: 'bout 2 feet from my iMac	theory > reality may be better? it's nice to be in a world where it's black and white, zero and one. no question. no ... well... MAYBE it's a one... it's one or the other, no middle. plus, it's the beginnings of computing theory. if I'm feeling evil, maybe I'll put up the Turing Problem for ya, one of these days

09-26-2003, 05:36 AM	#12 (permalink)
Kadath Muffled Location: Camazotz	To clear up: As cheerios knows, digital circuits are a big boolean expression. Analog circuits are a whole bunch of complicated math (including imaginary numbers) in which you have to do all sorts of calculations. While I suppose a Boolean expression is math...whatever. I've gotten depressed thinking about this. But logic != math. __________________ it's quiet in here