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Electrical circuit help
Hi there, here is the problem:
http://www.zen8722.zen.co.uk/ROB/Question7.jpg Now part (a) is easy enough, I've done that - Because each side has two 10kOhm resistors then V1 and V2 are equal (5V each) and you can ignore the middle resistor when calculating the current. Part (b) is where I am stuck. Thing is, I seem to remember doing questions like this a while ago, and I think that there might be something very simple that I am missing when trying to do this. Anyone got any ideas on how to do (b)? Thanks a lot in advance Robbie |
part (b) is a typical resistive bridge circuit.
The basic way to do it is to convert the delta resistor configurations into Y resistor configurations using the conversions. See the website below: http://www.allaboutcircuits.com/vol_1/chpt_10/12.html An easy way to do it is do use Thevenin and Norton equivalents. |
Why Lord, why did I look at this?! I knew it would kill my soul!!
Stupid EE degree, good for nothing, grumble grumble... |
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That is a great help :D In fact, that whole site looks very useful. Thanks again. |
I would have thought that it were a resistors in parallel and serial type problem ... now we see why I don't do EE :D
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/me had to drop electric circuits, but aced digital... so come back when they're gates, not resistors! :P
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Meltdown meltdown!!! Hurry click back botton before its too late
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Math describing physical systems vs. Boolean Algebra? |
theory > reality may be better? it's nice to be in a world where it's black and white, zero and one. no question. no ... well... MAYBE it's a one... it's one or the other, no middle. plus, it's the beginnings of computing theory. if I'm feeling evil, maybe I'll put up the Turing Problem for ya, one of these days ;)
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To clear up:
As cheerios knows, digital circuits are a big boolean expression. Analog circuits are a whole bunch of complicated math (including imaginary numbers) in which you have to do all sorts of calculations. While I suppose a Boolean expression is math...whatever. I've gotten depressed thinking about this. But logic != math. |
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