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Jakejake 09-24-2003 09:06 AM

Electrical circuit help
 
Hi there, here is the problem:

http://www.zen8722.zen.co.uk/ROB/Question7.jpg

Now part (a) is easy enough, I've done that - Because each side has two 10kOhm resistors then V1 and V2 are equal (5V each) and you can ignore the middle resistor when calculating the current.
Part (b) is where I am stuck. Thing is, I seem to remember doing questions like this a while ago, and I think that there might be something very simple that I am missing when trying to do this.
Anyone got any ideas on how to do (b)?

Thanks a lot in advance

Robbie

goddfather40 09-24-2003 07:34 PM

part (b) is a typical resistive bridge circuit.

The basic way to do it is to convert the delta resistor configurations into Y resistor configurations using the conversions.

See the website below:
http://www.allaboutcircuits.com/vol_1/chpt_10/12.html

An easy way to do it is do use Thevenin and Norton equivalents.

Kadath 09-24-2003 08:38 PM

Why Lord, why did I look at this?! I knew it would kill my soul!!
Stupid EE degree, good for nothing, grumble grumble...

Jakejake 09-25-2003 01:44 AM

Quote:

Originally posted by goddfather40
part (b) is a typical resistive bridge circuit.

The basic way to do it is to convert the delta resistor configurations into Y resistor configurations using the conversions.

See the website below:
http://www.allaboutcircuits.com/vol_1/chpt_10/12.html

An easy way to do it is do use Thevenin and Norton equivalents.

Wow, thanks a lot :)
That is a great help :D

In fact, that whole site looks very useful. Thanks again.

Sapper 09-25-2003 05:10 AM

I would have thought that it were a resistors in parallel and serial type problem ... now we see why I don't do EE :D

cheerios 09-25-2003 09:02 AM

/me had to drop electric circuits, but aced digital... so come back when they're gates, not resistors! :P

iamjero 09-25-2003 09:40 AM

Meltdown meltdown!!! Hurry click back botton before its too late

Kadath 09-25-2003 11:12 AM

Quote:

Originally posted by cheerios
/me had to drop electric circuits, but aced digital... so come back when they're gates, not resistors! :P
Amen to that, sister. Analog hard, digital easy. Logic > Math any day.

Xell101 09-25-2003 01:15 PM

Quote:

Logic > Math any day.
???...Math = Logic

CSflim 09-25-2003 01:28 PM

Quote:

Originally posted by Xell101
???...Math = Logic
dunno...presumably it means
Math describing physical systems vs. Boolean Algebra?

cheerios 09-25-2003 09:33 PM

theory > reality may be better? it's nice to be in a world where it's black and white, zero and one. no question. no ... well... MAYBE it's a one... it's one or the other, no middle. plus, it's the beginnings of computing theory. if I'm feeling evil, maybe I'll put up the Turing Problem for ya, one of these days ;)

Kadath 09-26-2003 05:36 AM

To clear up:
As cheerios knows, digital circuits are a big boolean expression. Analog circuits are a whole bunch of complicated math (including imaginary numbers) in which you have to do all sorts of calculations. While I suppose a Boolean expression is math...whatever. I've gotten depressed thinking about this. But logic != math.


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