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		#1 (permalink) | 
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			 Addict 
			
			
			
			
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				math problem
			 
			250.....b......d    
		
		
		
		
		
		
		
			---- = --- x --- 60.......a......c A has 2 be 30 or 32 bcd can be 34,38,40,41,42,43,44,46,49,50,52,60,66,70,80,90,100 it needs 2 come out even 2 each other. and if anyone can help me and tell me how ecactly u do it? had 2 put the dots in between the numbers cuz if not they get close 2 geter and they dont look like fractions Last edited by Smackre; 08-19-2003 at 10:13 AM..  | 
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		#3 (permalink) | 
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			 Devils Cabana Boy 
			
			
			
			
				
			
			Location: Central Coast CA 
				
				
				
				
				
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		 if you are going to give us a math problem dont use 2 inplace of to, its just silly 
		
		
		
		
		
			
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		#4 (permalink) | 
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			 Rookie 
			
			
			
			
				
			
			Location: Oxford, UK 
				
				
				
				
				
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		 U hav2 cansL T fracshnz  
		
		
		
		
		
			![]() 250/60 = 25/6 so 25/6 = bd/ac a is 30 or 32 I understand; but by 'bcd can be....(list)' do you mean b x c x d must be one of the list, or that each of b, c, and d must be picked from the list. Can we repeat numbers? If so... I like: a=30 b=100 d=100 c=80 Can you fill us in on exactly what it's all for? 
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		#6 (permalink) | 
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		 dexlarge understands me right.  yes those numbers are for each one not added to geter.  sorry about the 2's it comes from 3 years of eq heh.  how exactly do you do this easy takes me like 4 hours to do one of these problems and i need it for a grinder at work. I need to be able 2 place 250 with other numbers and do the same problem 
		
		
		
		
		
		
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		#8 (permalink) | 
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			 Rookie 
			
			
			
			
				
			
			Location: Oxford, UK 
				
				
				
				
				
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		 Just pick one of the numbers for a, then you only have to solve b,c,d. Either b or d has to be quite large in order to get the 125 for bd/c (assuming a=30). So pick high-ish numbers for them Seeing as the smallest c can get is 34, they have to multiply to at least 4250 - restricting your choice even further. So select b and d, divide the product by 125 and see if it's on your list for c. 
		
		
		
		
		
			Probably not the quickest way, but simple and works... perhaps someone kind with a bit of 1337 5k!11z will knock up a program/script for you if you're likely to be doing it regularly. 
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	I can't understand why people are frightened of new ideas. I'm frightened of the old ones. -- John Cage (1912 - 1992)  | 
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		#16 (permalink) | 
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			 Rookie 
			
			
			
			
				
			
			Location: Oxford, UK 
				
				
				
				
				
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		 ermm..  cowlick - there were some more equations  
		
		
		
		
		
			![]() Namely: a list of possible values for the four variables. If you still want a script knocking up, tell me a bit more about the grinder... 
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	I can't understand why people are frightened of new ideas. I'm frightened of the old ones. -- John Cage (1912 - 1992)  | 
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