Quote:
Originally Posted by Crompsin
Now for one of those hellish math problems on the SAT:
If I cover my exhaust in PAM and wrap aluminum foil pouches of OreIda tater tots around it... how many miles would it take to cook them? Assume I have a 1100CC Honda engine, 2.5" pipes, and a 55 mph speed limit.
|
For the sake of simplicity, I'll assume the PAM, exhaust pipe, foil, and packaging function as a system to form a 50% efficient exchanger. The outside temperature here is 45°F and the Tater Tots will start frozen at at 32°F. The gear ratio allows your bike to go 55mph at 1700RPM, releasing roughly 5000cc of exhaust gas at 1200°F, transferring one quarter of that (50% heat exchange and air has half the specific heat of steel) to the metal.
At a surface temperature of 300° and air temperature of 45°, the average heat applied to the entire surface of the tater tots at any time is 150°F. Tater tots are approximately 50% water and 50% starch, giving them a specific heat of approximately 2.5 joules per gram. Fortunately, this is approximately the mean specific heat of the exhaust pipe and air flowing over the bike. This means that riding at 55mph will will be the equivalent of baking them in an oven set to 150°.
The cooking instructions for tater tots specify that they should be baked at 450° for 8 minutes. 450° for 8 minutes is equivalent to 150° for 23 minutes. Because the approximate specific heat of the exhaust pipe and air flowing is 2.5 and the specific heat of the air in a baking oven is approximately 1.0, the cooking time can be divided by 2.5
For any amount of tater tots less than or equal to the number that it would take to cover the whole exhaust system, the approximate cooking time is 10.5 minutes. At 55mph, you would cover just under 11.5 miles in 10.5 minutes, so assuming that the bike is fully warmed up, plan to make an 11.5 mile trip to cook your taters, 12.5 miles if you like them extra crispy.