11-26-2004, 06:36 PM | #1 (permalink) |
Upright
|
[vb6] find and replace?
what is a way to code in vb6 a find and replace option like that in microsoft word?
i know how to code the normal find command but i still cant figure out how to find a word and show how many times a word has appeared in a line of text help needed thank you |
11-27-2004, 12:31 PM | #2 (permalink) |
Guest
|
I'm not sure what the one in microsoft word is like, but the vb one is
replace (<stringexpression>,<findexpression>,<replaceexpression>,start,count,vbCompareType) as String Here are some examples showing variations in the count value. I'm replacing i's for x's, always starting at position 1, and replacing 1,2,3 and then finally all (-1) instances of i's with x's: ? replace("a string with characters in it, various text etc.","i","x",1,1,vbTextCompare) a strxng with characters in it, various text etc. ? replace("a string with characters in it, various text etc.","i","x",1,2,vbTextCompare) a strxng wxth characters in it, various text etc. ? replace("a string with characters in it, various text etc.","i","x",1,3,vbTextCompare) a strxng wxth characters xn it, various text etc. ? replace("a string with characters in it, various text etc.","i","x",1,-1,vbTextCompare) a strxng wxth characters xn xt, varxous text etc. If you want to count how many times a word appears in a line of text you can either do a regular find, contained in a loop. Or you could tokenise the line into an array of words, load them into a collection and then count how many matched each collection key. What exactly do you want to do? |
11-27-2004, 05:38 PM | #4 (permalink) |
Devils Cabana Boy
Location: Central Coast CA
|
i have a weird way to do it.
Dim intext As String Dim searchtext As String Dim replacetext As String Dim outtext As String Dim numberfound As Integer Dim buff() As String Dim i As Integer intext = "testl testltesttestltest" searchtext = "l" replacetext = "q" buff() = Split(intext, searchtext, , vbBinaryCompare) Do Until i = UBound(buff) outtext = outtext & buff(i) & replacetext i = i + 1 Loop
__________________
Donate Blood! "Love is not finding the perfect person, but learning to see an imperfect person perfectly." -Sam Keen |
11-28-2004, 11:14 AM | #7 (permalink) |
Devils Cabana Boy
Location: Central Coast CA
|
oh yeah that part
numberfound=ubound(buff) ubound gives the upper bound of an array, since it splits the string into an array everywhere the search string occurs and it, it will break it into one more peices then the time it occurs, since it starts with zero, the ubound of the array is the total times it is found.
__________________
Donate Blood! "Love is not finding the perfect person, but learning to see an imperfect person perfectly." -Sam Keen |
11-30-2004, 12:16 PM | #8 (permalink) |
Tilted
Location: reno,nv
|
a way to count occurences of one string inside of another:
Dim S As String Dim position As Long Dim SearchString As String Dim count As Long S = " This is a great sentence. It is not very long, but is also quite lame. It is however unimportant and is not very exciting" SearchString = "is" count = 0 position = InStr(S, SearchString) Do Until position = 0 count = count + 1 position = InStr(position + 1, S, SearchString) Loop debug.print count End Sub its not fully tested but seems to work kevin |
12-01-2004, 02:15 PM | #10 (permalink) | |
Upright
|
Quote:
everytime i try to print count it gives me "0" |
|
Tags |
find, replace, vb6 |
|
|