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#2 (permalink) | |
Location: Waterloo, Ontario
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Quote:
The correct method of isolation will be so simple that you'll wonder why you didn't see it, yourself. Try doing this: Code:
1/a + 1/b = 1 1/a = 1 - 1/b (isolate the term with the wanted variable) a = 1/(1 - 1/b) (reciprocate both sides) The first two should be obvious. Neither a nor b may be zero, since division by zero is undefined. The third provision may come as a surprise but (1 - 1/b) may not be zero, either, since we divide by it. In other words, b ≠ 1. You can even see that this must be so because, in the original equation, if b were one, then the reciprocal of a must be zero, which is pretty hard to do (mild understatement)... |
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#3 (permalink) |
“Wrong is right.”
Location: toronto
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OF COURSE the answer ends up coming from Waterloo, Ontario....
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#4 (permalink) |
Insane
Location: Kansas City, MO
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Yeah, I feel kind of silly after actually sitting down and putting some effort into it. I reallized I had thought way to much about it.
1/a + 1/b = 1 ab(1/a) + ab(1/b) = ab b + a = ab b/a + a/a = ab/a b/a + 1 = b b/a = b - 1 b = a(b - 1) a = b/(b - 1) Although, I admit that you solution was much easier and more intuitive. Thank you kindly for your insight. Herk
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easy, math, question, seemingly |
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