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Old 12-13-2004, 08:03 PM   #1 (permalink)
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Math Problem (Help ASAP!)



Evaluate. Give mathematical reasons for your answer.

Please some one help me quick!

Edit: Would the answer just be C due to a jump discontinuity or something? I doubt it but I got nothing..

Last edited by Munku; 12-13-2004 at 08:07 PM..
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Old 12-13-2004, 08:10 PM   #2 (permalink)
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Wouldn't that just be negative one? (I could very well be WAY off.)
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Old 12-13-2004, 08:23 PM   #3 (permalink)
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i believe it's undefined. haven't done it in a while, but when you approach from the left you get one answer and from the right you get another answer, therefore, it's undefined
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Old 12-13-2004, 08:27 PM   #4 (permalink)
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Yeah, it's called the sigma function or something. The limit is undefined, but if there is a plus or a minus sign in the limit notation, then the answer is going to be + or - 1 depending on whether or not it's a + or a - in the limit. Hard to explain.
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Old 12-13-2004, 09:21 PM   #5 (permalink)
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edited - checked math, it is undefined since approaching from left the limit is different than approaching from right, so limit is undefined.
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Last edited by MageB420666; 12-13-2004 at 09:25 PM..
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Old 12-13-2004, 09:24 PM   #6 (permalink)
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Quote:
Originally Posted by MageB420666
Use L'Hospital's rule.



in this case f(x) = |x-c| and g(x) = x-c, so f'(x) = 1 and g'(x) = 1, so according to L'Hospital's rule, the limit is 1
The problem with that is the absolute value thrown in there. Thus, if you approach the limit from the left side, the function is negative 1, but if you approach it from the right side, the function is positive 1. For that reason, L'Hospital's rule is wrong. Good rule though.
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Old 12-13-2004, 09:26 PM   #7 (permalink)
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Quote:
Originally Posted by sandinista
The problem with that is the absolute value thrown in there. Thus, if you approach the limit from the left side, the function is negative 1, but if you approach it from the right side, the function is positive 1. For that reason, L'Hospital's rule is wrong. Good rule though.
realized that half a second after I hit the submit button and changed it, thanks though
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Old 12-14-2004, 05:51 PM   #8 (permalink)
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ummm... False!
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Old 12-17-2004, 02:37 PM   #9 (permalink)
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from the left, you get 1/-1, from the right you get 1/1. because as x approaches c from the left and it reaches teh limit, it will become just less than 0, and frmo teh right just over zero, since the numerator is always positive and the denominator is + or -, you get 1 or - 1. if the limit is reached at x = c, then there is no solution since x - c != 0
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