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Munku 12-13-2004 08:03 PM

Math Problem (Help ASAP!)
 
http://munku.onestop.net/math.jpg

Evaluate. Give mathematical reasons for your answer.

Please some one help me quick! :confused:

Edit: Would the answer just be C due to a jump discontinuity or something? I doubt it but I got nothing..

soma 12-13-2004 08:10 PM

Wouldn't that just be negative one? (I could very well be WAY off.)

mandal 12-13-2004 08:23 PM

i believe it's undefined. haven't done it in a while, but when you approach from the left you get one answer and from the right you get another answer, therefore, it's undefined

sandinista 12-13-2004 08:27 PM

Yeah, it's called the sigma function or something. The limit is undefined, but if there is a plus or a minus sign in the limit notation, then the answer is going to be + or - 1 depending on whether or not it's a + or a - in the limit. Hard to explain.

MageB420666 12-13-2004 09:21 PM

edited - checked math, it is undefined since approaching from left the limit is different than approaching from right, so limit is undefined.

sandinista 12-13-2004 09:24 PM

Quote:

Originally Posted by MageB420666
Use L'Hospital's rule.



in this case f(x) = |x-c| and g(x) = x-c, so f'(x) = 1 and g'(x) = 1, so according to L'Hospital's rule, the limit is 1

The problem with that is the absolute value thrown in there. Thus, if you approach the limit from the left side, the function is negative 1, but if you approach it from the right side, the function is positive 1. For that reason, L'Hospital's rule is wrong. Good rule though.

MageB420666 12-13-2004 09:26 PM

Quote:

Originally Posted by sandinista
The problem with that is the absolute value thrown in there. Thus, if you approach the limit from the left side, the function is negative 1, but if you approach it from the right side, the function is positive 1. For that reason, L'Hospital's rule is wrong. Good rule though.

realized that half a second after I hit the submit button and changed it, thanks though ;)

bobophil 12-14-2004 05:51 PM

ummm... False!

Karkaboosh1 12-17-2004 02:37 PM

from the left, you get 1/-1, from the right you get 1/1. because as x approaches c from the left and it reaches teh limit, it will become just less than 0, and frmo teh right just over zero, since the numerator is always positive and the denominator is + or -, you get 1 or - 1. if the limit is reached at x = c, then there is no solution since x - c != 0


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