05-15-2004, 07:39 AM | #1 (permalink) |
Psycho
Location: Where the night things are
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The 33 1/3 second mystery #33
Put on your math hats, kids!
What is the next number in the sequence: 13, 15, 21, 23, 27 Explain your answer.
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There ain't nothin' more powerful than the odor of mendacity -Big Daddy |
05-15-2004, 01:02 PM | #4 (permalink) |
comfortably numb...
Super Moderator
Location: upstate
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28...
5 numbers between the first set, 3 numbers between the second set, ergo, 1 number between the third set...
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05-16-2004, 07:21 PM | #10 (permalink) |
Crazy
Location: San Francisco
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31
The numbers in the sequence are 13 15 21 27 They can be expressed as the prime numbers [11 13 17 19 23] added to [2 2 4 4 4]. If we add the next sequential prime number to the first matrix, it would be 27. Of the second matrix, two repeats itself twice, so four should repeat itself four times, so let's add four to it. 27+4=31, the next number in the sequence. I'm probably making this problem waaaay more complicated than it should be, but still...
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f-e-r-n-w-e-h is actually a gross misspelling of the name "gregory" |
05-17-2004, 03:33 AM | #11 (permalink) |
Addict
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27 isn't a prime number.
29 plus 4 is 33, but I mean can you just assume 4 will repeat itself four times. Maybe, it's a prime number and then the next two odd multiples of 3, then the next prime number, then the next two multiples of three. In this case the answer would still be 33. |
05-22-2004, 09:37 AM | #17 (permalink) |
Crazy
Location: San Francisco
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35?
Since we know 29 is "integral to the answer" and it's the next prime number in the sequence, we know that the question is now which number comes next in THIS sequence: [2, 2, 4, 4, 4] and we're gonna add that to 29. It looks like it would be an even number, and 6 is the next one, so.... 35?
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f-e-r-n-w-e-h is actually a gross misspelling of the name "gregory" |
05-22-2004, 11:34 AM | #18 (permalink) |
Psycho
Location: Where the night things are
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35 is indeed the correct answer. The key to this puzzle is looking at different numerical bases. Were it constructed in binary or hexidecimal, that would have been a dead giveaway. Instead, I chose octal, and started with two integer primes, where 11=13, 13=15, 17=21, 19=23, 23=27, and 29=35.
I was all but certain you folks had it cracked with the 2,4 logic postings starting on the 16th. An eight-legged fuzzy bunny to fernweh
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There ain't nothin' more powerful than the odor of mendacity -Big Daddy |
Tags |
#33, 1 or 3, mystery |
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