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For the second part:
Given
A = total number of all cards in the production run
c = total number of 1:1 cards in the deck
n = total number of cards in the pack
Odds of one out of all of the cards being the 1:1 card
P1 = 1 in A / (c*n)
Odds of one one out of the remaining cards being the 1:1 card
P2 = 1 in (A-1) / [(c-1)(n-1)]
Odds of two cards in the pack being the 1:1 card
P1 * P2
I'm not 100% sure of this answer, but it seems intuitive, and plugging test numbers into Excel seems to give appropriate answers.
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"We must have waffles. We must all have waffles, forthwith. Oh, we must think.
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-- Professor Goldthwait Higginson Dorr, Ph.D.
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