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Probably really simple, I'm just not seeing it
If a ball is thrown into the air with a velocity of 40ft/s, its height i feet is after T seconds is given by y=40T-16T^2. Find the average velocity for the time period beginning when T = 2 and lasting
.5 sec
.1 sec
.05sec
.01 sec.
I got .5 sec at -32. Which is the correct answer. But when I try the same way for the other numbers I get the wrong answer. For the -32 I just put in .5 for T. Thanks.
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