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ALRITE, 2nd part the (x+ blah question.
use pascel's triangle
1 - 0
1 1 - 1
1 2 1 - 2
1 3 3 1 - 3
1 4 6 4 1 - 4
partial triangel. in ur case, u need to go up to level 27, but that later.
(x+a)(x+b) follows triangle level 3 --- indicated by - 2 at the side cuz ur using 2 (x+?)'s ------- x^2 + ax + bx + ab is ur answer.
as u can see, there are 1 x^2 value, 2 x values, and 1 (1) value. its more clear in the next example
(x+a)(x+b)(x+c) follows lvl 4 --- indicated by - 3 at side.
u get 1 set of x^3, 3 sets of x^2, 3 sets of x, 1 set of (1).
now u start cooking.
within the sets of x^2, all available answers are the single combinations of a,b, and c. then those multiplyed by x^2
so.. ax^2 + bx^2 + cx^2 <---- this is the (3) of the pascal triangle
second part of this is sets of x, all multiplyed combinations are with 2 letters, so u get also get 3 --- abx + bcx + cax
now. if u carry that through to the 27th level ("marked" as - 26) then u have x^27 + x^26(all single combinations of a-z, 26 of em) + x^25(all double combinations of a-z, some number) ... etc until the last number - abcdef....z
dunno if it helps... heh... i tried...
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