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Proof:
r = radius (in mm) of the smallest ring.
The number of bytes per ring = (Innermost ring circumference)/(spacing) = (2*pi*r)/(1 mm) = 2*pi*r
The number of rings = 70 mm - r
The number of bytes b(r) = 2*pi*r*(70-r)
At maximum number of bytes, the derivative of b(r) = -4*pi*r + 140*pi = 0; r = 35 mm
This is a maximum, not a minimum b/c the second derivative is negative.
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