Quote:
Originally posted by Artsemis
I understand what is being said; but wow, this is confusing.
I see it like this...
If you start out with 3 doors, choose one, and Monty reveals one of the wrong doors. That, to me, is the same as you walking up there with only 2 doors to choose from - one wrong and one correct.
There were initially 3 doors to choose from; 33% of them contain the correct door, 66% contain the wrong one.
One door is eliminated.
There is now 2 doors (consider the other one gone - it doesn't matter anymore); 50% of the doors are correct, and 50% are wrong.
The way I see it -- Using the logic stated above, if before the show, there was 5 doors, and Monty decided to remove two of the wrong ones before the show - would that effect your odds? 
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Think of this:
Say there were a billion doors. You pick one at random. Monty Hall then eliminates 999,999,998 of them, leaving you with two options.
By your logic, your chance of success is 50-50. But seriously, what are the chances that with a billion doors you guessed correctly from the beginning?