I understand what is being said; but wow, this is confusing.
I see it like this...
If you start out with 3 doors, choose one, and Monty reveals one of the wrong doors. That, to me, is the same as you walking up there with only 2 doors to choose from - one wrong and one correct.
There were initially 3 doors to choose from; 33% of them contain the correct door, 66% contain the wrong one.
One door is eliminated.
There is now 2 doors (consider the other one gone - it doesn't matter anymore); 50% of the doors are correct, and 50% are wrong.
The way I see it -- Using the logic stated above, if before the show, there was 5 doors, and Monty decided to remove two of the wrong ones before the show - would that effect your odds?
