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ok, here's some preliminary analysis
Lets break it into 3 events.
Event:
1) Minus 2 Red, Add one blue=> -2R+B
2) Minus 2 Blue, Add one=> -B
3) Minus 1 Red, 1 Blue, Add 1 Red=> -B
When you have 3 balls left, there are 4 possible states
3-1) 3 R
3-2) 2R 1B
3-3) 1R 2B
3-4) 3B
Last edited by dimbulb; 11-25-2003 at 04:56 PM..
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