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charliex · 11-07-2003, 10:26 PM

basically each bit in the 32 bit return value is set to 1 if a drive exists, and each bit position corresponds to a drive letter

all you have to do is, test the bit position corresponding to the drive letter to determine if it exists.

In C you could use a bitfield and let the compiler handle all the tests for you. either otherwise its simply doing an and with a 1&lt&ltbit_number where the first is drive A.

Code:

val = GetLogicalDrives( );
	for(i=0;i&lt26;i++) {
		printf("drive %c: is %s\n", i+'A',ret&(1&lt&lti)?"Available" : "Not Available");
	}

thatd list if the drive is available or not (barring typos)

11-07-2003, 10:26 PM	#4 (permalink)
charliex Junkie Location: North Hollywood	basically each bit in the 32 bit return value is set to 1 if a drive exists, and each bit position corresponds to a drive letter all you have to do is, test the bit position corresponding to the drive letter to determine if it exists. In C you could use a bitfield and let the compiler handle all the tests for you. either otherwise its simply doing an and with a 1&lt&ltbit_number where the first is drive A. Code: val = GetLogicalDrives( ); for(i=0;i&lt26;i++) { printf("drive %c: is %s\n", i+'A',ret&(1&lt&lti)?"Available" : "Not Available"); } thatd list if the drive is available or not (barring typos)