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Silvy · 10-07-2003, 12:33 AM

Actually, I think the original graph (of e^(-x)), goes from +infinity (for x approaches -infinity) to approaching zero (for x approaches +infinity)

(and of course the graph crosses the x=0 point at y=1)

Rotating would yield y= -infinity to y approaches zero
(for x=<-infinity, +infinity>).

I would have no idea on the "center of mass" value, I do not know the concept.

Edit: I think I misunderstood Frozen North's post, we probably share the same notion of the graph.

10-07-2003, 12:33 AM	#3 (permalink)
Silvy paranoid Location: The Netherlands	Actually, I think the original graph (of e^(-x)), goes from +infinity (for x approaches -infinity) to approaching zero (for x approaches +infinity) (and of course the graph crosses the x=0 point at y=1) Rotating would yield y= -infinity to y approaches zero (for x=<-infinity, +infinity>). I would have no idea on the "center of mass" value, I do not know the concept. Edit: I think I misunderstood Frozen North's post, we probably share the same notion of the graph. __________________ "Do not kill. Do not rape. Do not steal. These are principles which every man of every faith can embrace. " - Murphy MacManus (Boondock Saints)