View Single Post
Old 09-08-2003, 07:47 PM   #4 (permalink)
cheerios
Banned
 
Location: 'bout 2 feet from my iMac
this part: ( the top quarter of the wire is 4x the bottom 3/4 is 10-4x) doesn't make any sense to me. as for hte rest of it, well, it's a related rates problem, isn't it?

so, what's the area of a circle? A = πr^2
what about the circumfrence? C = 2*π*r
what's the area of an equilateral triangle? A = 1/2*x*h, where h = the height of the triangle
sin60(degrees) = h/x, so h = xsin60,
so A = 1/2*x*xsin60.
now the trick is to relate all of those, so that you eliminate all the variables besides x.

first step: A = π*r^2 + 1/2*x*x*sin60. only radius isn't meaningful right now, so get rid of using the circumference equation. that's how I'd approach it, anyway. remember that the circumference of your circle will be 10 - 3x, where x is the length of a side of your triangle!
cheerios is offline  
 

1 2 3 4 5 6 7 8 9 10 11 12 13 14 15 16 17 18 19 20 21 22 23 24 25 26 27 28 29 30 31 32 33 34 35 36 37 38 39 40 41 42 43 44 45 46 47 48 49 50 51 52 53 54 55 56 57 58 59 60 61 62