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Pennington · 07-22-2003, 02:25 AM

You don't perchance happen to know how many grams of non-volatile naphthalene (C10H8, MW = 128g-mol-1) must be dissolved
in 500g of benzene (C6H6, MW = 78.0 g-mol-1) to lower the freezing point by 18.3°C?
Note: Kf = 5.1°C/m for benzene.

[edit]- I think the answer is 23g

07-22-2003, 02:25 AM	#203 (permalink)
Pennington Banned Location: Autonomous Zone	You don't perchance happen to know how many grams of non-volatile naphthalene (C10H8, MW = 128g-mol-1) must be dissolved in 500g of benzene (C6H6, MW = 78.0 g-mol-1) to lower the freezing point by 18.3°C? Note: Kf = 5.1°C/m for benzene. [edit]- I think the answer is 23g Last edited by Pennington; 07-22-2003 at 02:42 AM..