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You don't perchance happen to know how many grams of non-volatile naphthalene (C10H8, MW = 128g-mol-1) must be dissolved
in 500g of benzene (C6H6, MW = 78.0 g-mol-1) to lower the freezing point by 18.3°C?
Note: Kf = 5.1°C/m for benzene.
[edit]- I think the answer is 23g
Last edited by Pennington; 07-22-2003 at 02:42 AM..
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