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Because it was a bad estimate, you can find some actual numbers here.
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Thanks awfully, boy do I feel embarrassed! Sorry for the incorrect info, folks.
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So how does the dog's jaw (which is made of bone) withstand those hundreds of pounds of pressure it's exerting? How do the dog's teeth withstand over two orders of magnitude more pressure than bone? Not that I agree with SF's assessment, but I think your numbers are a bit exaggerated.
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When an animal's jaw closes around a bone, the force is distributed from a large surface area (the teeth and jaws) down to a smaller surface area on the cutting edges of the teeth. This has the effect of spreading the bite force out over the architecture of the jaw in the biting animal, while in the -bitten- animal all that force is instead focused onto the receiving surface via the cutting edges of the biter's teeth. It's all about sectional density; the same way you don't have to push very hard to apply a few dozen pounds per square inch, a dog doesn't have to push very hard to produce two hundred. Pointed or edged teeth translate that few pounds of force (applied to the tooth by the several square inches of your jaw) into multiples of that number of pounds of force applied to the target object by the much smaller-in-area contact surfaces of the teeth, the number depending upon how sharp the cutting edges are. Remember, even with less and a third of the average bite strength of a dog, we humans still tear our way through lots of meat. And we're made of meat too.