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But C isn't moving at C (see what I did there?).
OK, smart-assness over, I don't think you've constructed your question quite right. A and C depart point B at the speed of light in opposite directions. From B, both A and C will always be seen as moving at the speed of light since B is stationary. B is moving at the speed of light as seen from both A and C. That's an important distinction because when A or C looks at each other in reference to themselves, even though they're moving at the speed of light, the other is still moving at the speed of light - which is the same as B. If light departed from one of them back towards the other, it would depart at the speed of light in that direction, which is not zero to compensate for the direction of travel in the opposite direction but the actual speed of light. If the light was shone from C towards A and A wasn't 100% efficient, eventually the light from C would eventually catch A.
At least as I understand it.
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