n0nsensical

Note other than H2O these are all ionic compounds, K2Cr2O7 and Na2SO3 are really 2K+ + Cr2O7(2-) and 2Na+ + SO3(2-)
Write the half-reactions (looked these up in a table, not sure if you're 'supposed' to do that)
Reduction:
Cr2O7(2-) + 14H+ + 6e- -> 2Cr(3+) + 7H2O
Oxidation:
SO3(2-) + H2O -> SO4(2-) + 2H+ + 2e-

Balance the electrons
Cr2O7(2-) + 14H+ + 6e- -> 2Cr(3+) + 7H2O
3SO3(2-) + 3H2O -> 3SO4(2-) + 6H+ + 6e-

Sum
Cr2O7(2-) + 8H+ + 3SO3(2-) -> 3SO4(2-) + 2Cr(3+) + 4H2O

Get the 8H+ from 8HCl and conveniently there are also 8Cl- in the products. I hope that's everything but I'm not very good at this either. :P

Moles of SO2 in the formation of one mole I2? I don't see any SO2s or I2s. That sounds like a different problem. you need some sort of equation.