Turn signals are controlled by a device called the thermal flasher. A thermal flasher is an electric device that opens and closes a circuit automatically at regular intervals because of alternate heating and cooling of a bimetallic strip that is heated by a resistance element in series with the circuit being controlled.
In other words, strip heats up, makes contact, turns light on. Strip cools down, breaks contact, turns light off. The timing of the interval is dependent on how much current is drawn by the bulbs in the signal indicator. The LED's draw significantly less current than a conventional bulb so that alters the interval, in most cases it makes it flash on and off very slowly, if at all.
The load equalizer fixes this problem by simulating the current draw of conventional bulbs, returning the interval to normal.
Now, on to your question...
Generally speaking, the 7.5 ohm equalizer should produce a slower flash interval than the 5.6 ohm equalizer since it's drawing less current and heating the bimetal strip more slowly.
Best way to figure out how much current each side uses is with Ohm's law (I=(V/R), where I=current, V=voltage, and R=resistance). Adapt this formula to calculate resistance with parallel circuits, and we get
. We know the voltage is 12 volts, just grab a multimeter, measure the resistance of your bulbs, plug in the values, and you have your answer.
Sorry that it's long winded, but hope this helps.