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Each time you split an I2 you make 2HI
think of it like this:
H-H + I-I =========> H I H I ========> H-I + H-I
Because you are taking two molecules of gas, and making two molecules of gas there is no change in volume or pressure. The point that is confusing you is that only HALF of the reacted gas is Iodine.
If you start with a 50/50 mis of Hydrogen and Iodine, and Iodone is consumed at 0.0037mol/L/s, then so is Hydrogen.
Therefore, unless you have invented a way of creating atoms from vacuum, you have generated HI molecules at 2 x 0.0037, which equals 0.0084mol/L/s.
I hope I've got that right, or they'll make me give my degrees back...
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Overhead, the Albatross hangs motionless upon the air,
And deep beneath the rolling waves,
In labyrinths of Coral Caves,
The Echo of a distant time
Comes willowing across the sand;
And everthing is Green and Submarine
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