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Pip · 12-02-2006, 11:34 AM

I feel the love here!

Sorry about the typo.

I suck at cubic equations. But since we know the answer is x = 3/7 then we know b = 1 must be an answer to

2b^3 - 9b^2 + 27b - 20 = 0

Which it is, if you sort of look at it. I divided by 2 and broke out (b - 1) just to see if I could still do polynomial divisions and got

(b - 1)(b^2 - 7b/2 +10) = 0

b^2 - 7b/2 +10 = 0 has no real roots. I think guessing answers and breaking out roots was the standard method we used back in highschool.

Good times.

12-02-2006, 11:34 AM	#23 (permalink)
Pip Likes Hats Location: Stockholm, Sweden	I feel the love here! Sorry about the typo. I suck at cubic equations. But since we know the answer is x = 3/7 then we know b = 1 must be an answer to 2b^3 - 9b^2 + 27b - 20 = 0 Which it is, if you sort of look at it. I divided by 2 and broke out (b - 1) just to see if I could still do polynomial divisions and got (b - 1)(b^2 - 7b/2 +10) = 0 b^2 - 7b/2 +10 = 0 has no real roots. I think guessing answers and breaking out roots was the standard method we used back in highschool. Good times.