Quote:
|
Originally Posted by Stiltzkin
Okay, I'm back, and it looks like a + 7 = 27 - 27b + 9b^2 - a is no good either because now we have two variables  |
Stiltzkin,
To step in for my truest math-love
pip who spanked my ass earlier, the +a,-a thing was a typo on her part earlier. It's -a, as you found - which gives a coefficient of 2 in front of the b^3 term. For the two variable issue, no prob, substitute a=b^3 and you only have one variable. The problem I'm having with this approach currently is that it will give 3 solutions to the problem, and this problem apparently only has one unique solution. Something is rotten in Denmark, as they say.
Off to cogitate.