pig

Awwwww....shucks...

If you want to run this stuff by me later, pop me an im. I got the results using the molecular weight of I2 being 253.xx as well...either way, your original numbers in the earlier post work out to give the equation as being the equation given in the link, with some room for experimental error.

If you assume that the equation looks like

Zn + I2 => ZnI2

then you should get a 1:1:1 ratio, using the molecular weight of I2 = 253.xxx.

If you use the equation as being:

Zn + 2I(-) => ZnI2

Then you would get a ratio of 1:2:1, using the molecular weight of I = 126.xx

Does that make any sense?

Its a factor of 2, which shows up either in the equation, or in the molecular weights. Let me know if I can do anything else; I'm a nerd for hire

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