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Iodine mol weight = 126.9 g/mol
Zinc mol weight = 65.49 g/mol
.86g zinc / 65.49 = 13.1 mM
3.00 iodine / 126.9 = 23.6 mM
I think the amount of zinc might be slightly off, but since the reaction required approx 2 moles of iodine for every 1 mole of Zinc, the formula should
be:
Zn(2+) + 2 I(-) <-> ZnI2
mM should be mMol
Last edited by rofgilead; 07-02-2006 at 05:43 PM..
Reason: Automerged Doublepost
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