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Maybe this will help in your googling... You're calculating steam quality.
The key is that the amount of energy present in Xkg of 250C 60bar liquid will be equal to Xkg of 100C 1bar gas/liquid mixture.
In:
250C 60bar Subcooled Liquid (hf) 1085.3 kJ/kg
Out:
99.62C 1bar Saturated Liquid (hf) 417.46 kJ/kg
99.63C 1bar Saturated Vapor (hg) 2675.4 kJ/kg
Solve the following system of equations:
1085.3X = 417.46Y + 2675.4Z
X = Y + Z
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Simple Machines in Higher Dimensions
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