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OK..
Liquid water at 60 bar and 250 degrees has H = 1085.8 Kj/Kg
Pf = 1.0 bar, so Tf = 99.6 degrees, therefore H = 2675.4 Kj/Kg
So, the excess that comes out is 2675.4 - 1085.8 = 1589.6 Kj/Kg
so, assuming a mass flow of 1kg/hr, the extra energy would be 1589.6Kj/Kg which would go to vaporization.
The answer is that 0.296 evaporated. How in the world did they arrive at that number ?
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