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keyshawn · 05-03-2005, 02:37 AM

I'd check over my work again, according to pg. 39 of this - http://homepage.smc.edu/geltner_peter/new4to6.pdf

The '1' constant in the numerator shouldn't be negative.

BTW, with that in mind, you end up with 2 + Sqrt(3) as the answer.

[If you don't change the negative sign, you get -2 + sqrt(3)

05-03-2005, 02:37 AM	#5 (permalink)
keyshawn Psycho	I'd check over my work again, according to pg. 39 of this - http://homepage.smc.edu/geltner_peter/new4to6.pdf The '1' constant in the numerator shouldn't be negative. BTW, with that in mind, you end up with 2 + Sqrt(3) as the answer. [If you don't change the negative sign, you get -2 + sqrt(3) __________________ currently reading: currently playing :