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There goes an hour of my work day - I think this is not an overly complicated problem. The best method of trying to solve it is to start with the beginnings as shown by miriad people above and work out what each letter is not.
Given that p=1, and can't be anything else, r has to be 0, which makes h =9.
From this start, you can deduce that none of OCUS are 5 (as the resulting bottom line would be either 0 or 1, then O needs to be even, but not 6 or 8, because it invalidates "R=0"
and so on.
From here I did a bit of If this, then that, until I got an invalid result.
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who hid my keyboard's PANIC button?
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