Quote:
|
Originally Posted by Yakk
And, if you had 20 equally-picky homosexuals, the chances of a pair being good enough is about 87%.
Given two parties, one homosexual and one heterosexual, where the homosexual party is uni-sex and the heterosexual party is male/female, and where the heterosexuals and homosexuals are equally picky/monogomous/etc...
What is the difference in party sizes such that both parties have the same chance of a pair forming?
|
It's not a difficult calculation. Let's start with the heterosexual party being 10 males and 10 females. This is 100 potential matches.
The formula for a single sex environment is x (x-1)/2. Using this, we get 45 potential matches at 10 people. To equal the 100 matches at the hetero party, you need 15 people 15(7)=105. If you up the hetero party to 20 of each sex, you get 400. To equal this, you need 29 at a single sex party 29(14) = 406.
So the answer is a little under 3/4 of the number at a hetero party, assuming the hetero party is equally split male/female. If that ratio is off any the number of matchups goes down.