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Old 03-14-2005, 07:19 AM   #10 (permalink)
the420star
Psycho
 
Location: Cow Country, CT
lets look at this in terms of a T... you have something coming in, and two things coming out... Kirchovs Current law states that the sum of currents at a Node, the point where all three things connect is 0. So using this as an example... lets say you have a light blub on one end like you example, that will act as a load a draw a given amount of the current from the system, leaving whatever is left to be used by razor in your example. so we get source(total current) = lightbulb + Razor....so you can see that as long as the needs of the razor dont exceed source - light bulb, then you have adiquate power. i dunno if this is enough info for you, i just banged this out quickly before class... post again if you have more ?s, i am a senior in an EE program... i should be able to clear this all up for you
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