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Originally Posted by Stompy
The only time I've ever used "u" with derivatives was like so:
Find the derivative of 1/(4-x^2)
u = x^2
du = 2x dx
the problem then becomes du/(4-u)^2
Since u is x^2, and du is 2x, it becomes 2x/(4-x^2)^2.
In other words... u substitution.
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The u substitution is more useful when you get to integrations. In diferentiation the u substitution mentioned above is what I was talking about - chain rule.