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Originally Posted by Augi
Kebo, but I do know calculus and I know that d(|x|)/dx is not constant.
d(|x|)/dx = { -1 , x<0 ; undefined , x=0 ; 1 , 0<x }
If you need to see how that is done, just break |x| into three functions: y(x) = { -x , x<0 ; 0 , x=0 ; x , 0<x } . The derivative of y(0) can't occur because of the conflicting limits as you approach 0- and 0+ (You are in calculus right?).
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that's absolutely correct. But according to sieger35's definition of an affine function
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If I'm not mistaken, an affine function is a linear form + a constant term.
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the derivative must be constant.
kevin
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or at least it must be constant over the range of values in question