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Originally Posted by jaded
good krwlz, i think you got the right answer!
it\'s ok to use GJ, but you made a mistake in the last step above:
-2R1+R2 should give you a zero row, therefore suggesting no solution.
-2R1+R2
(1 -2|1 1)
(0 0 |x x)
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My problem exactly.
And that 5 part theorem is only the things that are completley logically equivalent... Anything you can derive from there needs not be listed, because it is implied. Such as spanning is essentially, #3, and liniear indepenence is #2.