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Originally Posted by Thermopyle
hmmm, a long time ago i studied lin alg but a (2x2)- times a (2x2)-matrix shouldn't produce another (2x2)-matrix.
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Actually, thats not correct. a 2x2 matrix times a 2x2 matrix will equal a 2x2.
The sizes of the final matrix is easy - Drop the 2 inside numbers of the matrices and only use the outer two numbers (rows from the first matrix and columns from the second). Example: a 1x4 matrix times a 4x6 matrix will result in a 1x6 matrix. (keep in mind that the 2 inside numbers must be the same).
Other than that, i think a-j is right. The determinate of A is 0 therefore it does not have an inverse - which is what you would need to properly solve it. I believe there is no solution.