Quote:
|
Originally Posted by KnifeMissile
If that were the metric, then why isn't the chances of player 1 winning a 100%. After all, there is no card that could allow him to lose, right?
|
I don't know the specifics of the odds-making program the WOSP uses so I don't know if either of the following theories are actually the reason, but...
Theory One
As was mentioned earlier, a 4 on the river would have resulted in a split pot. Because only five cards are used to make up a hand, it doesn't matter that player two's 6th card is higher. But in the event that a pot is split and there is an extra chip left over, the player with the highest 6th card would get that extra chip. This is the only time a 6th card has any impact on winnings. So, since player two had the highest 6th card, he would have recieved a slightly larger portion of the pot. The odds-making program may have taken this into account and adjusted the percentages accordingly.
Theory Two
The odds-making program may not be able to handle percentage totals over 100%. Depending on the programing, it might not make sense to the computer for one player to have a 100% chance of winning and another player still have a 2% chance. To deal with this conflict,the program simply adjusted player one's percentage to accomadate player two's chances. I have seen odds-making programs that, in a situation like that, will allow for percentage totals over 100%, but not all programs are created equal.
So either the program was overly sophisticated or not sophisticated enough. Who knows?