Tilted Forum Project Discussion Community - View Single Post - Wrong probabilities on the World Series of Poker...

BonesCPA · 11-01-2004, 01:57 PM

Not having the winning hands memorized, I googled winning poker hands and came up with this answer:

http://govegas.about.com/cs/gambling...kerhandstp.htm

If another 4 was drawn, then player 2 wins. Three of a kind does not beat a straight. Therefore, since both players would have a straight, the high card holder would win. In this case, King high would win.

The 2% issue is a little more difficult. Since there are at least two 4's already out, the chance of pulling another 4 would probably be around 2 in 32 (assuming 6 players at the start - 12 dealt to players, four shown, four wasted). This would give about 6% chance to draw a four. From the 2% figure, I am going to assume they "knew" another four had already been wasted and then also rounded down. I am not 100% on this theory though.

11-01-2004, 01:57 PM	#2 (permalink)
BonesCPA No. It's not done yet. Location: sorta kinda phila	Not having the winning hands memorized, I googled winning poker hands and came up with this answer: http://govegas.about.com/cs/gambling...kerhandstp.htm If another 4 was drawn, then player 2 wins. Three of a kind does not beat a straight. Therefore, since both players would have a straight, the high card holder would win. In this case, King high would win. The 2% issue is a little more difficult. Since there are at least two 4's already out, the chance of pulling another 4 would probably be around 2 in 32 (assuming 6 players at the start - 12 dealt to players, four shown, four wasted). This would give about 6% chance to draw a four. From the 2% figure, I am going to assume they "knew" another four had already been wasted and then also rounded down. I am not 100% on this theory though. __________________ Back into hibernation.