Thread: Why .9r = 1
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Old 10-21-2004, 10:42 AM   #56 (permalink)
filtherton
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Quote:
Originally Posted by a-j
daking is correct the limit is 1.
The limit of y=sin(x)/x = 0/0, using l'hopital's rule the limit of y=cos(x)/1 as x->0 = cos(0)/1 = 1/1
I was refering to the limit as x goes to infinity because that is what he asked at the end of the particular post he was referring to.

Quote:
Originally Posted by molloby
I see where you're coming from but there is a difference between saying:

1/infinity = 0
and
1/x gets arbitrarily close to 0 as x gets arbitrarily large

Rigour goes a long way in maths.

Yeah, on second thought, i should have read things more carefully before i opened my vitual mouth.
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