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Wow, how is the limit of sin(x)/x as x->inf obviously 1?
This limit is obviously 0, since |sin(x)|<=1. Limit of |sin(x)|/x as x->inf = 0. Take a look at the epsilon delta definition of limit why this works.
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Yea it was late (4 am) when i was typing, for some reason was thinking about x to 0. I am aware the limit as x tends to infinity is 0.
The function i should of used was x sin(1/x) whose limit is 1 as x->inf.