Thread: Why .9r = 1
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Old 10-16-2004, 09:18 PM   #24 (permalink)
daking
Tilted
 
Quote:
Originally Posted by Paradise Lost
Ok, turns out I made another mistake.

x=.9r
[Substitute Time!]
.9r=.9r
9r=9r (Multi both by 10)
9r-.9r=9r-.9r (Sub by .9r)
8.1r=8.1r (Doing da Math)
8.1=8.1 (Divide both by r)
1=1 (Divide both by 8.1)

Just weird algebra, don't know what they're trying to get at.
also, Paradise Lost's proof is not correct either, there is no logical implication from one statement to the next. Unless you inteded to Show that that 1=1. Also dividing by r makes no sense. "r" isnt a number.

One might as well do

x=100r
[Substitute Time!]
100r=100r
1000r=1000r (Multi both by 10)
1000r-100r=1000r-100r (sub by 100r)
900r=900r(doing da math)
900=900(divide both by r)
1=1 (divide both by 900)

Do you see it makes no sense. The above doesnt mean that 100=1!
daking is offline  
 

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