Thread: Why .9r = 1
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Old 10-16-2004, 06:17 AM   #12 (permalink)
AngelicVampire
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x = .99r
10x = 9.90r
10x - x = 9.9r - .9r
9x = 8.9r1 (because if we are dealing with say any number of 9s the multiplied number will have one less dp than the original number, so will produce a 1 at the end of that number...)
x = 0.9r

I do not see the point? x = 0.999999999999
10x = 9.99999999999
9x = 8.99999999991
x = 0.99999999 ~1

What is this meant to prove? That 0.999999999999999999999999999999999999 is ~1 for most things?


This is similar to what our maths lecturers told us... n/infinity = 0. X * n/infinty != 0... its an approximation.

Last edited by AngelicVampire; 10-16-2004 at 06:21 AM..
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