filtherton

As much as i hate asking people for help, i'm stumped. The problem involves integration by partial fractions. If you want to help me the most just give me a hint, don't solve the fucker for me.

Anyways the problem is to integrate the function 1/(x^4+1) by way of adding and then subtracting from (x^4+1) to create a difference of squares.

My first idea was to subtract two from the denominator resulting in

1/[(x^4-1)+2]

which gets factored moreso down to

1/[(x^2+1)(x+1)(x-1)+2]

normally you'd want to make a substitution, but with all of the factors down there that doesn't seem to make much sense.

That's where i'm stuck.
Maybe i should've made the substitution
u=(x^4-1) giving the
du=4x^3dx
x=(u-1)^(1/4)

That would give me the integrand
1/[4(u-1)^(3/4)*(u+2)]

Anyways, i've got to work. If you think i'm on the right track let me know. Thanks in advance.