Thread: A calc question
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Old 05-19-2004, 08:41 AM   #3 (permalink)
Giltwist
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Location: Pennsylvania
Using polynomial division,

(2x - x^3 - 1) / (x - 1) = -x^2-x+1

Plugging in x=1 from the point (1,2)

(2x - x^3 - 1) / (x - 1) = -1

Therefore the slope of the tangent line is -1. Since all lines have the format y=mx+b where m is the slope, we now have

y=-x+b

using the point (1,2) again

2=-1+b

b=3

so the equation of the tangent line is

y=-x+3
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