tehhappyboy

Remember, a sideways cylinder creates rectangular cross sections, so it's actually easy to integrate. X is a constant, length of the cylinder, y is the variable cord length of the circle parallel to the ground and you just integrate over Z the height of the circle (or water level). Bingo. Take Defninite integral. Or plug in X for the upper bound, take the antiderivative and then plug it into a Second Fundamental theorm equasion (F(b)-F(a), F being the antiderivative of your equasion for area f)and you have an equasion for the volume.

(Didn't do it, maybe the formula for the circle is your tough sqrt. Remember, sqrt is just x^1/a so deriving is easy.

The solution is now trivial.

Enjoy.

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