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Just to add to firebirdta's solution. He is right about the primitive data types and the referential data types.
What you did was trying to do it in the middle way.
When I first saw your if statement, I thought you were evaluating chars but were actually doing strings.
Another possible solution is
if(args[1].charAt(0) == 'x')
Either way works, it just a matter of what kind of data you're dealing with.
The equal method actually deals with object which is another type of referential data types.
Other possible solutions are
if(args[1].equalsIgnoreCase("x"))
In this case, 2 strings are compared regardless of case size.
But one problem with firebirdta's solution. What if the user decides to use the bigger case X? (eg: "java maths 3 X 4" instead of "java maths 3 x 4") Then your if statement would return false since it is only looking for the lower case x. In this case, I suggest you use the if(args[1].equalsIgnoreCase("x"))
One of the fundamentals of data structuring and alogrithms is the ability to predict human behavoior involved when it comes to running programs. Programmers are actually expected to build foolproof programs, meaning that we try to anticptate all possible situation that occurs when the user use the program.
A elite programmer once said
"Programming is an race between the universe and programmers. Programmers build bigger, better and more idiot-proof programs while the universe produce more idiots. So far, the universe is winning"
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